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X^2=2X+10.5
We move all terms to the left:
X^2-(2X+10.5)=0
We get rid of parentheses
X^2-2X-10.5=0
a = 1; b = -2; c = -10.5;
Δ = b2-4ac
Δ = -22-4·1·(-10.5)
Δ = 46
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{46}}{2*1}=\frac{2-\sqrt{46}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{46}}{2*1}=\frac{2+\sqrt{46}}{2} $
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